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Stoichiometry part 1
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Replies : 2
Last Replied :22/06/2009
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18/06/2009 14:21:02
Title:
Stoichiometry part 1
Status : Answered by Moderator
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MEGHNA HADA
Joined: 07/05/2009
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if x% of a solute of molecular mass(M.) is present in a solution having a density of 'd'gm/cc, calculate the molality, molarity , mole fraction if x% is by volume.
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18/06/2009 14:39:10
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Re:Stoichiometry part 1
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ARPIT SHARMA
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M=10xd/Molecular Weight
mole fraction=100xd/moles ofA[1000D-10XD]
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22/06/2009 16:21:12
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Re:Stoichiometry part 1
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Kulvinder Singh
Joined: 29/12/2007
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x% by volume means x gm of solute in 100 cc of solution (i.e. 100d gm of solution)
Molarity = (x/Mo)/0.1
Molality = (x/Mo)* 1000/(100d-x)
Mole fraction of solute = (x/Mo)/(x/Mo + (100d-x)/1
Mole fraction of solvent = 1- mole fraction of solute
Cheers
Kulvinder Singh
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