Home
Courses
Questions & Discussions
Blog
Resources
IITJEE
AIEEE
100Percentile IITJEE Login
100Percentile IITJEE Registration
Filter
All
Low
Medium
High
Filter
All
No
Yes
Filter
All
New Title
Answered but not Reviewed
Answered and Reviewed
Answered by Moderator
p and c  XML
Questions & Discussions » Maths Questions
Go to last reply
Author Message
Status : Answered but not Reviewed Difficulty Level: - Importance for Exam:  -
[Avatar]
Shivam Rastogi
Joined: 15/08/2008
Expert Level
 
Total points
0
 
 
Total Messages
30
 
 
Contact Me   (Offline)
 
 
the no. of n-bit(0&1) strings having exactly k 0's and no 2 0's consecutive is_________
 
Author Message
Status:  Answered but not Reviewed
[Avatar]
sahil sharma
Joined: 17/06/2009
Expert Level
 
Total points
0
 
 
Total Messages
15
 
 
Contact Me   (Offline)
 
 
let the no of 1's be = a
 no of 0's = k
 total permutations are (a+k)!/(a!*k!) - *
 now consider the case where at least two 0's are conseq. then, total elements are (assuming 00 to be 1 element) =(a+k-1) total permutations are
 (a+k-1)!/(a!* [k-1]!) - **
 subtracting ** from * gives our answer

 PS: plz tell me if i'm wrong!!
 
Author Message
Status:  Answered but not Reviewed
[Avatar]
sahil sharma
Joined: 17/06/2009
Expert Level
 
Total points
0
 
 
Total Messages
15
 
 
Contact Me   (Offline)
 
 
oh ..one small mistake...we multiple ** by k!/(2!&[k-2]!)
 here this denotes the no. of ways of choosing 2 0's out of k 0's...
 
 
 
   
Go to Forum: 
Questions & Discussions » Maths Questions
Home  |  About Us  |  Contact Us  |  Site Map  |  Terms of Service  |  FAQs  |  Feedback  |  Privacy Policy
© 100Percentile Education Pvt. Ltd. , All rights reserved.
Glossary  : IITJEE | IITJEE 2010 | IITJEE Practice tests | Online practice tests | IITJEE preparation | AIEEE preparation | Detailed Analysis report | Relative analysis system